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Question 15: Do the vectors below form a basis for R3? If so, explain. If not remove as many vectors as you need to form a ba
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D (A–B)2 – (A-B) (A-B) A - BA - AB+B² JP A,B are non-commutative, then ABEBA. So, the given equality is invalid in general -B

187 AT A,BT = B Now, (AB)T - BAT-BA #AB in general Take A= 132 62) B 2 - Then AT=A, BT = B AB - (62)(23):G4) = - AB [ 4 symme

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