A 24-g sample of radioactuve iodine decays in such a
way that the mass remaining after t days is given by
m(t)=24e^-0.089t
where m(t) is measured in grams. After how many dYs is there only
17 g remaining?
_______days
m(t) = 24e-0.089t
Now we have to solve for
m(t) = 17
24e-0.089t = 17
e-0.089t = 17/24
Taking natural log both the sides
ln e-0.089t = ln (17/24)
-0.089t ln e = ln (17/24)
-0.089t = ln (17/24) Since, ln e = 1
-0.089t = -0.34484
t = -0.34484 / -0.089
t = 3.87 Days Answer
Hope This Helps!
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