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QUESTION 1 The data given in question-1 is used in the remainder of the postlab assignment questions. A 2.0 g of unknown material was dissolved in 9.00 mL of water (density of water = 1.0 g/mL) The freezing point of pure water is 0.00 °C and Kf of water is 1.86 °C/m. If the solution made above shows a new freezing point at -2.76 °C, calculate the molality (m) of this solution Hint: First find the change in temperature (deviation from original freezing point) Change in temperature = KfXm: solve for m OA. 2.50 m OB. 1.48 m O C 5.1336 m O D.9.21 m A 2.0 g of unknown material was dissolved in 9.00 mL of water (density of water - 1.0 g/ml) The freezing point of pure water is 0.00 °C and Kf of water is 1.86 °C/m. If the solution made above shows a new freezing point at -2.76 °C, calculate the moles of unknown dissolved in this solution Hint: Molality (m) = moles of substance / kg of solvent 0 0.1332 moles 0 0.01332 moles O 2.25X10-3 moles O 0.41 moles A 2.0 g of unknown material was dissolved in 9.00 mL of water (density of water - 1.0 g/mL) The freezing point of pure water is 0.00 °C and Kf of water is 1.86 °C/m. if the solution made above shows a new freezing point at -2.76 °C, calculate the molar mass (MW) of the unknown material Hint: Use the moles of unknown (calculated in question 2) and the grams of the unknown used to determine the MW Moles = g/MW O A. 1.503 g/mol B. 15.03 g/mol O C 150.37 g/mol D.0.1503 g/mol

Same Question and data but different parts. Please solve for all three. Last attempt left