Question

When playing American roulette, the croupier (attendant) spins a marble that lands in one of The probability of the marble landing on a green or even slot is the 38 slots in a revolving turntable. The slots are numbered 1 to 36, with two additional slots (Type an integer or a simplified fraction.) labeled and 00 that are painted green. Consider the numbers 0 and 00 as neither even nor odd. Half the remaining slots are colored red and half are black. Assume a single spin of the roulette wheel is made. Find the probability of the marble landing on a green or even slot.

Answer 1

P(A) = n(E)/n(S)

Where P(A) is the probability of an event A

n(E) is the number of favorable outcomes

n(S) is the total number of events in the sample space.      

There are 18 even and 18 odd-numbered slots, the remaining 2 are 0 and 00, which are neither even nor odd(both are green in color).

Probability of selecting a green slot = 2/38 = 1/19

Probability of selecting a even slot = 16/38 = 8/19

probability of selecting a green or even slot = Probability of selecting a green slot + Probability of selecting a even slot

probability of selecting a green or even slot = 1/19 + 8/19 = 9/19 = 0.474

These two are independent events.

Answer is 9/19 or 0.474.