please help and explain (ask, discuss - and share your ideas, but no need to submit)...
Please explain step by step in a dumbed down version -- if you can Based on the graph f(t) sketched to the left, (a) fill out approximate values in the table of A(x) = $* f(t)dt. (b) For what value of x in the interval (0,4] does A(x) reach a minimum? (Hint 1. you see the graph of f(t) not A(x). Hint 2. A(2) is not the minimum. ) y = f(t) 1 (c) Sketch an approximate graph of the...
please help Discuss it please but do not submit. Your participation in this discussion will help you understand the first part of the next lesson. (a) Sketch a graph of A(x) = S * ++ dt by first sketching a graph of t2 and by counting small squares. (b) Note that A(1) = 0 (Why?). (c) Also, note that the FTC gives us A'(x) = x2. Why? Based on this information how can we obtain an algebraic formula for A(z)?
Can someone please help explain this problem Find the critical numbers of f(x) . x.a- 0.3. 12 12 12 0.4,7 0,3, 12 0,3, 12 10. pts A) B The graph of a function y-f) is shown. At which V point(s) are the following true? (a) and are both positive. dx dx dy 0) dand dr are both negative (C) dx is negative but d? is positive. f(A dy g (x) HINT of the curve at that point
Consider the graph of the function g shown below. The domain of g is [0,10], and the graph of g is comprised of two line segments and a quarter circle. 1. The function F is defined on [0,10] . It is an antiderivative of g and satisfies F(7)=0. Sketch a graph of F 2. Use your knowledge of area to compute F(4). Explain your reasoning. 3. Write a formula for F using an appropriate integral of g. 4. The function...
0/1 points |Previous Answers SCalcET6 6.1.028. My Notes Ask Your Tea Sketch the bounded region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label its height and this graph.) width. (Do this on paper. Your instructor may ask you to turn y 2,y 82,2x + y = 3, x 2 0 Then find the area S of the region S 5/3 Need Help?Talk to a Tutor Submit...
6. Please provide BRIEF answers to the following questions about the major concepts and ideas of this course. (a) Say that a 6 0. What does this tell us about the vectors ã and b? (b) Given a function far,y), how would you compute the vector f? (c) What does it mean to say that (a, b) is a critical point of a function f(x,y)? (d) What does the integral // 1 dA represent? (e) What does the integral ///...
how do you these questions? i need help please Absolute Value Functions Name: 1. Sketch the graph of the function. State the intercepts, and the domain and range. f(x) = 12x +11 2. Write the following as a piecewise function a. y = 15x +11 b. y = 1-2(x+3)(x - 1)
Please discuss problems in your group and arrive at a solution together. If your entire group is confused, ask for help. Each student is responsible for understanding the material covered in this group work assignment. 1. For each function f(a), find the domain. Then find the critical numbers. Recall: critical numbers are a-values in the domain where f'(x)=0 or f'(x) DNE. (a) f(z) = 2+2 Domain: critical numbers = (b) f(x) = re Domain: critical numbers = 2. Let f(x)...
Consider the function f(1) = 22 - 62+5 Answer all parts: (a) - (). (a) The vertex is (b) The axis of symmetry is (c) The 2-intercept(s) is (are) (Enter the list, separated by a comma. (d) The y-intercept is y = (e) Sketch a graph of f(x) = 22 - 61 +5. Instructions: To sketch the graph, click on the following locations: (1) vertex (2) the x--intercepts 10 10 0 -10 After graphing answer the following: (f) What is...
3. Consider the following piecewise function (a) Draw an accurate graph of f(). (b) As always, f(x), has an infinite number of antiderivatives. Consider an antiderivative F(r). Let us assume that F(r) is continuous (we don't usually have to specify this, but you will see in the bonus part of the question why we do in this case). Let us further assume that F(2) 1. Sketch an accurate graph of F(r). MATH 1203 Assignment #7-Integration Methods Due: Thurs., Apr. 4...