For a particular cell based on the reaction: 3 AgCl(s) + Al(s) + 3 Ag(s) +...
QUESTION 9 For a particular cell based on the reaction: 3 AgCl(s) + Al(s) - 3 Ag(s) + A13+ (aq) + 3 CHaq) E - +1.884 V at 298K. What is the value of the equilibrium constant. K. at 298 K for the reaction? Enter your answer in exponential format (example 1.23E-4) with two decimal places and no units If you use the constants Rand Fin your calculation, use ONLY these values: R-8.31451 J/K F = 96,485 C/mol
Part A For the galvanic cell that uses the reaction 2 Al(s) + 3 Cu2+ (aq) + 2 A13+ (aq) + 3 Cu(s) the value of n in the relationship AG'-nFEis Express your answer as an integer. Η ΑΣΦ ?
16. Calculate AG in wate agin) (2 pts) and (2 pts) and (3 points) points for the following reaction at 290 K. Mg(s) + Fe(aq) + Mg(aq) + Fe(s) - 1.84 V AGE ANT 8314 K-mol F-96,485 )/V-mol K R 17. Balance the following redox reaction in acidic aqueous solution. Mno. (a) + Br" (a) → MnO2 (s) + Broj (na) 18. Consider the following voltaic cell designation: Al(s) AP+(aq) || Ni+(aq) Ni(s) a. (3 points): Write a balanced chemical...
A voltaic cell is constructed using silver and aluminum. The following is the unbalanced redox reaction: Ag+ (aq) + Al(s) Ag (s) + A13+ (aq) What is the correct, balanced redox reaction that occurs in the cell? O A 5 Ag+ (aq) + 3 AI (5) - 5 Ag (s) + 3 A13+ (aq) O B. Ag* (aq) + 4 AI (5) ► Ag (s) + 4 A13+ (aq) OC 3 Ag* (aq) + Al(s) — 3 Ag (s) +...
The standard electromotive force of the cell Pt/H2(g)/HC/// AgCl(s)/Ag has been determined from 0 - 90 °C. The potential in volts as function of temperature in °C is represented by the following linear equation (F = 96485 C/ mol) E°(T) = 0.24-3.9x10-4 T Determine AS° at 25° for 12 H2 (g) + AgCl(s) + HCl(aq) + Ag(s) Select one: a. 27.5 J/mol K b. -47.5 J/mol.k c. 47.6 J/mol K d. 37. e. -37. Ashwaq sent a photo
Consider the Gibbs energies at 25 ∘C. SubstanceSubstance ΔG∘f (kJ⋅mol−1)ΔGf∘ (kJ·mol−1) Ag+(aq)Ag+(aq) 77.177.1 Cl−(aq)Cl−(aq) −131.2−131.2 AgCl(s)AgCl(s) −109.8−109.8 Br−(aq)Br−(aq) −104.0−104.0 AgBr(s)AgBr(s) −96.9−96.9 (a) Calculate ΔG∘rxn for the dissolution of AgCl(s)AgCl(s). kJ⋅mol−1 (b) Calculate the solubility-product constant of AgCl. K= (c) Calculate ΔG∘rxnΔGrxn∘ for the dissolution of AgBr(s)AgBr(s). kJ⋅mol−1kJ⋅mol−1 (d) Calculate the solubility-product constant of AgBr. K=K=
Use the standard half-cell potentials listed below to calculate the standard free energy(K]for the following reaction occurring in an electrochemical cell at 25°C. Pb 2+ (aq) +2e--- Pb(s) E* - -0.13 Volt A13+ (aq) + 3 e-Al(s) E* =-1.66 volt a. 1.53 b. - 886 c-434 d. - 443 e. -1036 What is the standard free energy Gº) in Kilojoules for the reaction below at 298 Kelvin: Farady's constant = 96,485 joules/V. mole e Zn2+ (aq) + 2e ......> Zn(s)...
Calculate ΔG°rxn,298 and ΔGrxn,298 for the following. a) Ag+(aq) + Cl-(aq) -> AgCl (s) b) Ag+(aq) + I-(aq) -> AgI (s) c) Ag+(aq) + NO3-(aq) -> AgNO3 (aq) d) Ag+(aq) + SO4 2-(aq) -> Ag2SO4(aq) e) Ba 2+(aq) + 2Cl- (aq) + 2H2O (l) -> BaCl2 • 2H2O f) Ba 2+(aq) + 2NO3-(aq) -> Ba(NO3)2 (aq) ΔGo, 298 values for 1M solutions NO3 -108.74 -33.41 SO42 -744.53 -618.41 Cl -109.789 -1296.32 W2 -384.138 Anions (kJ/mol) Cations (kJ/mol) -51.57 -66.19 Ag...
A voltaic cell set up utilizing the reaction Cu(s) + 2 Ag+ (aq) → Cu2+ (aq) + 2 Ag (s) has a cell potential of 0.45 V at 298 K. Describe how the potential of the cell will change as the cell is discharged. At what point does the cell potential reach a constant value? Explain your answer
The standard electromotive force of the cell Pt/H2(g)/HC/// AgCl(s)/Ag has been determined from 0 to 90 °C. The potential in volts as function of temperature in °C is represented by the following linear equation (F = 96485 C/ mol) E°(T) = 0.24-3.9x10-4 T Determine AG° at 25° for 12 H2 (g) + AgCl(s) – HCl(aq) + Ag(s) Select one: a.-23.2 kJ/mol b. 21.2 kJ/mol C.-22.2 kJ/mol d. 23.2 kJ/mol e. 22.2 kJ/mol