Question

Pane od Question A: In the Y3+ cation, in its ground state, how many electrons have m=0 ? Question B: In the Gat cation, in its ground state, how many electrons have m = +1 ? Question C: In the NiS+ cation, in its ground state, how many electrons have m = 0 ? Question D: In the Zn2+ cation, in its ground state, how many electrons have both m = 0 and s = +1/2 ? Question E: In the Cr6+ cation, what is the effective charge felt by a valence electron? Question F: In the Hanion, what is the effective charge felt by a valence electron?

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Answer 1

A Eleettonic configuration of yst isi (Al. no. 39 ) y3t : 15² 2 2 2p% 35² 3pl 30° 45² 4p6 6 n-1 0, 1, 2, m an l related as to tl s has two value: + or - 1/2 of s orbital (2=0) cubital (1:1), m 2 1,0,+1 d orbital (1=2) -2,-1, 0, +1, +2 , mo P m d 3 M20 mo 24p6 y : Yitriem yst (39) a 15²28²2pb 35² 3pt 3 do 45 The nor y electron having me zo is = [16] m2.0 mit! m2+1 d Р The noi of m-0 flectronic configuration of Gent is Gat = 152 25 22 pl 3s²3p6 3d10452 electron having me = t1 is G {e from 2P+ 2eju 3p+ 2e08 3d } © Electronic configuration of list i Hist = 162 28² 2p% 38² 3p * 3d5 45 the no. of electrons having me to is [1] fzegu om 15 + 24" from +2 e ºfron 2P+ 2€ from 35 + 2e from 3 p + le from 3d} m-0 P d au hàng Tin > Electronie Configuration g za 4 i h 2 : 19² 292 2p% 3g? 3p"Id" The no. g electron hawly mazo and satis [6 § le from is + le juge as + le fou ap tid from sp the four 3? tle from 3d = 16

E с 6+ : nuclear Charge 1 2 2 2 2p6 3s2 3p6 24 -f+хоз +x or 35 + $х б•& S+ 3x 2 2 ? 24 - 11.2 2 - 12. ЯК E н" nuclear Charige = 1-0.30 =10.70 с Be has the greatest radies. с

Н x 2 Я Br 360p = 36e 24 23be Sh gonization Energy & 1 cé 2180" AM = 18e KH :3te kt alse" Rbt Ca 2+ = 180 lower no. of é higher of e higher will be its g. E 24 has the lowest size he as it has lower no. be squeened has the highest gonezation Energy og er than nou g protons ca side will 2t ca 1 it + fellt Fe2teaq) + 2 H2 H H H is an oridizing agent) anel it get redused to ne so felso is requiring agent 29

Colig og is neutral molecule to all oxidation states adds to zero ire, As we know, os sg & ors 0.5 tois go=0 H2+1 go O-2 6x + 12 x + 1 + 3x(-2) -0 6 M +12-6 20 uuni 6 n 2-6 2-1 1 Қ Oxidation state of carbon in this molecule is when weater nafour condeuses at 100°c, the entropy of anverse is positie. ( Entropy uneworse is always positive } The entropy g surrounding must be positive because is as it is not spontaneous negative entropy of system process ܝܐ