Question

A gaseous stream containing 20.0 mole% ethanol and 80.0 mole% air is to be cooled from 60.0°C to 9.65°C in a condenser at the constant pressure of 1 atm to liquefy some of the ethanol. The gas stream entering the condenser has a pressure of 1.00 atm, flows at a rate of 10.0 mole/s and, at 60°C, is well above the saturation temperature (42.4°C). As a result of the cooling, 1.75 mole/s of liquid ethanol (Top = 78.5°C) leaves the condenser as a liquid stream in addition to a gas stream containing all of the materials which were not liquefied. What is the rate of heat transfer in the condenser? Possible Helpful Information For Ethanol Cp = 0.06134 kJ/(mol-°C) as a gas Cp = 0.1031 kJ/(mol-°C) as a liquid For air Cp = 0.02894 kJ/(mol.°C) In order to receive a full credit, you must show (i) flow chart, (ii) energy balance, (iii) reference state, and (iv) enthalpy table.

Answer 1

using given data and energy balance we can find the required heat removal

Jomoll 60°C Condensor a.bic Pobie 80% i ojo elhe on 10% mel, 97.6592 Molo flor of ethe 10x0.g=& mal Mob. Plan of Ara a mols. Inlet A3 Rete. Apply Energy Belonie on Con clense Calling In-Out - Conso. 2 (01031)(Ti-Ti ) +01008894)( 1170)-(1-75) (0-1031)(9.63-60) (0-95)(0-66194)(9065-60-4 (0-09854) (9-65-60) +020 Rex = 91.513 UJ / Hi Ho IU/ml) Component Elhonallges) Liquid 1-45724 3.099 50191

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