In an urn, there are 3 blue balls and 2 red balls. A ball is selected...

Question

Question

Answer 1

Answer #1

a)

P(2nd blue) =P(1st is red and 2nd blue)+P(!st is blue and 2nd blue)

=(2/5)*(4/5)+(3/5)*(3/5)

=17/25

b)

P(1st was blue given 2nd was blue )=P(!st is blue and 2nd blue)/P(2nd is blue)

=(3/5)*(3/5)/(17/25)=9/17

Answer 2

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