Question

to and you 5. MATLAB can also solve second order equations symbolically using the Symbolic packages. The help page https://www.mathworks.com/help/symbolic/solve-a-single-differential-equation. html#f1-11214 shows examples of how this works. Code this up for the same equation and see if you get the same answer. If you don't (and you probably won't), try simplifying the answer after you get it to see if it matches then. Note: You'll need to define the symbolic function y(t) here in order to use the same notation we did above. Also, you need to make a new variable Dy = diff(y), otherwise the function notation won't work properly. 6. Next, we're going to look at what these solutions look like for a frequency close to the resonant frequency of the system. Consider the following differential equation day +24004y = (2400 – W) * 2400 * cos(wt) dt2 for a chosen frequency w, with y(0) = 0 and y'(O) = 0. The (2400 – W). 2400 factor on the right hand side is only there to rescale the solution appropriately; it doesn't have a physical interpretation. Use the second order solver (or your own) and plot the results for w=2300, w=2350, and w = 2390. Discuss what you see in the solution. To make other comments, it may be helpful to hear what these solutions sound like; to do that, if you have an anonymous function f(t) that is the solution, you can use tVals = linspace(0,2, 2*8192); 2 sound(f(tVals)); If you have a symbolic function, you can use matlabFunction like in the previous example to get an anonymous function.

QUESTION 6 please help

MATLAB

Answer 1

`Hey,

Note: If you have any queries related to the answer please do comment. I would be very happy to resolve all your queries.

clc

clear all

close all

format long

s={'w=2300','w=2350','w=2390'};

ct=1;

for w=[2300,2350,2390]

syms y(t) Dy(t)

figure;

Dy(t)=diff(y);

eq=diff(y,2)+2400^2*y==(2400-w)*2400*cos(w*t);

cond=[y(0)==0,Dy(0)==0];

y(t)=dsolve(eq,cond);

ezplot(y,[0,2]);

title(s{ct});

ct=ct+1;

end

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Kindly revert for any queries

Thanks.