[9 total pt(s)] A one-way analysis of variance was conducted on 5 groups. The total standard...
latalp A one way analysis of variance was conducted on groups. The total standard devation was calculated to be 1. The total degrees of freedom was found to be 4 and the resulting p value was found to be 0.05. Use the given Information to fill out the rest of the ANOVA teble. freedom? What is the number of treatment degrees 2 pts) You are correct. Your receipt no. is 159-5174 Previous Tiles What is the denominator degrees of freedom...
[9 total pt(s)] A one-way analysis of variance was conducted on 5 groups. The total standard devation was calculated to be 3. The total degrees of freedom was found to be 64 and the resulting p-value was found to be 0.1. Use the given information to fill out the rest of the ANOVA table. What is the number of treatment degrees of freedom? [1 pt(s)] Submit Answer Tries 0/3 What is the denominator degrees of freedom for the test statistic?...
[9 total pt(s)] A one-way analysis of variance was conducted on 6 groups. The total standard devation was calculated to be 1. The total degrees of freedom was found to be 23 and the resulting p-value was found to be 0.1. Use the given information to fill out the rest of the ANOVA table. What is the number of treatment degrees of freedom? [1 pt(s)] Submit Answer Tries 0/3 What is the denominator degrees of freedom for the test statistic?...
A one-way analysis of variance was conducted on 5 groups. The total standard devation was calculated to be 2. The total degrees of freedom was found to be 22 and the resulting p-value was found to be 0.25. Use the given information to fill out the rest of the ANOVA table. Calculate SST [1 pt(s)] Incorrect. Tries 2/3 Submit Answer Calculate SSE [1 pt(s)] Submit Answer Incorrect. Tries 1/3 Calculate SSA [1 pt(s)] Incorrect. Tries 1/3 Submit Answer Calculate the...
[9 total pt(s)] A one-way analysis of variance was conducted on 6 groups. The total standard devation was calculated to be 1. The total degrees of freedom was found to be 23 and the resulting p-value was found to be 0.1. Use the given information to fill out the rest of the ANOVA table. Calculate SST [1 pt(s)] Submit Answer Tries 0/3 Calculate SSE [1 pt(s)] Tries 0/3 Submit Answer Calculate SSA [1 pt(s)] Tries 0/3 Submit Answer Calculate the...
There is no other information given other then what is in the picture. Please help I am having difficulty answering the question. [9 total pt(s)] A one-way analysis of variance was conducted on 5 groups. The total standard devation was calculated to be 2. The total degrees of freedom was found to be 13 and the resulting p-value was found to be 0.05. Use the given information to fill out the rest of the ANOVA table. What is the number...
Investigators working on commericially cultivating shrimp are interested in determining the best conditions in which for them to grow. They are interested in knowing what impact water temperature (either 25 C, 30 C) and the salinity level (10 %, 25 % and 40 %) have on the growth of shrimp. Three replicates were used for each of the 6 possible treatment combinations. Post-larval shrimp were placed in each of the 18 tanks and fed the same amount of food. After...
A study was carried out to assess the effect of a new medication in reducing blood pressure. In the trial, 59 subjects were enrolled, of which 30 were randomly allocated to receive a new treatment, while 29 received a control medication. After 20 weeks in the study, each subject's blood pressure, , was measured, leading to the following summary statistics: 9.63, 9.79, 1.41. With and representing the mean blood pressures in the treatment and control groups respectively, it is desired...
Samples of three different species of amphibian (frog, toad and salamander) were collected and dissected and the number of parasites found within each was counted and recorded. The researchers are interested in determining whether the distribution of parasites across species is different. The number of parasites within each sample was counted and recorded. Toads Frogs Salamanders 15 8 6 15 3 3 5 16 4 2 2 5 8 4 4 6 2 8 18 0 4 6 2 7...
According to genetic theory, a particular cross of two cultivars of sorghum should produce plants with red, yellow, or white seeds in the proportions 9/16, 3/16 and 1/4. Data from an experiment yielded the following results. Red Yellow White Count 216 6785 We wish to assess whether the data agree with the theory. What is the null hypothesis for the test? There is no difference among the colours. The probabilities given by genetic theory are correct. The probabilities are not...