DETAILS LARLINALG8 8.4.027. Let u = (1 - 1,3i), v = (21, 2 + i), w...
Problem #6: Let u = (i, 21,6), v = (5,-21, 1+i), w = (2-i, 21, 8 + 6i). Compute (u: v) wu Express your answer in the form a + bi and enter the values a and b (in that order) into the answer box below, separated with a comma. Problem #6: -35,27 Values of a and b, separated with a comma. Just Save Submit Problem #6 for Grading Problem #6 Attempt #3 Your Answer: Attempt #1 13,27 0/2x Attempt...
DETAILS LARLINALG8 8.4.051. Use the inner product (u, v) = U_V1 + 2uzvą to find (u, v). = (2i, -i) and v = (i, 7i) (u, v) =
1 Problem 4. Let V be a vector space and let U and W be two subspaces of V. Let (1) Prove that ifU W andWgU then UUW is not a subspace of V (2) Give an example of V, U and W such that U W andWgU. Explicitly verify the implication of the statement in part1). (3) Proue that UUW is a subspace of V if and only if U-W or W- (4) Give an example that proues the...
[-/1 Points] DETAILS LARLINALG8 4.3.003. Is W a subspace of V? If not, state why. Assume that has the standard operations. (Select all that apply.) W is the set of all 2 x 2 matrices of the form [1] V = M2,2 W is a subspace of V. W is not a subspace of because it is not closed under addition. W is not a subspace of V because it is not closed under scalar multiplication. Submit Answer Viewing Saved...
DETAILS LARLINALG8 5.R.013. Consider the vector v = (2, 2, 6). Find u such that the following is true. (a) The vector u has the same direction as v and one-half its length. (b) The vector u has the direction opposite that of v and one-fourth its length. u (c) The vector u has the direction opposite that of v and twice its length. U=
DETAILS LARLINALG8 8.4.039. Find the Euclidean distance between u and v. - (6,0), v = (1,1) d(u, v) =
DETAILS LARLINALG8 4.R.023. Determine whether W is a subspace of the vector space V. (Select all that apply.) W = {f: f(0) = -1}, V = C[-1, 1] W is a subspace of V. W is not a subspace of V because it is not closed under addition. W is not a subspace of V because it is not closed under scalar multiplication.
Let u = (2,-1,1), v= (0,1,1) and w = (2,1,3). Show that span{u+w, V – w} span{u, v, w} and determine whether or not these spans are actually equal.
Q6 - 21 Let u : | -71, v-| -31, and w=| 27 |. It can be shown that-3u-2v-w=0. Use this fact (and no row 4 - 21 27 2 x1 operations) to find x1 and X2 that satisfy the equation73 4-7 2 2 (Simplify your answers.)
Problem 4. Let V be a vector space and let U and W be two subspaces of V. Let (1) Prove that if U g W and W g U then UUW is not a subspace of V 2) Give an ezample of V, U and W such that U W andW ZU. Explicitly verify the implication of the statement in part (1) (3) Prove that UUW is a subspace of V if and only ifUCW or W CU.' (4)...