[-/1 Points] DETAILS LARLINALG8 4.3.003. Is W a subspace of V? If not, state why. Assume...
DETAILS LARLINALG8 4.R.023. Determine whether W is a subspace of the vector space V. (Select all that apply.) W = {f: f(0) = -1}, V = C[-1, 1] W is a subspace of V. W is not a subspace of V because it is not closed under addition. W is not a subspace of V because it is not closed under scalar multiplication.
Determine whether the set w is a subspace of R3 with the standard operations. If not, state why. (Select all that apply.) W = {(x1, 1/X1, X3): X1 and xy are real numbers, X1 + 0) W is a subspace of R W is not a subspace of R because it is not closed under addition. Wis not a subspace of R because it is not closed under scalar multiplication. X
DETAILS LARLINALG8 4.R.084. ASK YOUR TEACHER Determine whether each statement is true or false. If a statement is true, give a reason or cite an appropriate statement from the text. If a statement is false, provide an example that shows the statement is not true in all cases or cite an appropriate statement from the text. () The set w = {(0,x2,x): and X" are real numbers) is a subspace of R. False, this set is not closed under addition...
16. [0/1 Points] DETAILS PREVIOUS ANSWERS LARLINALG8 4.1.002 Find the component form of the given vector. v= – 5² +47 X y 3 2 х -6 -5 -4 -3 - 2 -1 Determine whether the set, together with the indicated operations, is a vector space. If it is not, then identify one of the vector space axioms that fails. The set {xy): x 29,729) The set is a vector space. The set is not a vector space because it is...
Let be the set of third degree polynomials
Is a subspace of ? Why or why
not?
Select all correct answer choices (there may be more than
one).
a.
is not a subspace of because it is not
closed under vector addition
b.
is a subspace of because it contains the zero
vector of
c.
is not a subspace of because it is not closed
under scalar multiplication
d.
is a subspace of because it contains only
second degree polynomials
e.
is...
Determine if the set V = {at? | a € R} is a subspace of the vector space P2 = {ao +ajt + azt? | ao, a1, az ER}. You may assume that vector addition in P2 is given by the usual addition of polynomials and that the scalars used in scalar multiplication are real numbers. If you decide that Vis a subspace of P2, then identify the zero vector in V and explain briefly why Vis closed under vector...
Viewing Saved Work Revert to Last Response 8. DETAILS LARLINALG8 3.R.027. Find (Al and A-11. 1 0 -2 A= 03 2 -5 7 6 (a) Al (b) A-11 9. DETAILS LARLINALG8 3.R.068.
Math 287, ME/MQ 01 3. Consider the set W of all 2 x 2 matrices of the form with the standard operations of matrix addition and scalar multiplication (a) Show that this set is closed under the operation of addition, (b) Ifu,EW and c is a real munber, show that cu + v) cu + cv. (c) Display the zero vector for W.
Determine if the given set is a subspace of P4. Justify your answer. All polynomials of degree at most 4, with integers as coefficients. Complete each statement below. The zero vector of P4 in the set because zero an integer The set v closed under vector addition because the sum of two integers an integer The set closed under multiplication by scalars because the product of a scalar and an integer an integer Is the set a subspace of P4?...
(a) State whether the following statement is true or false. The follow set is a subspace of P2, where P2 is the set of all polynomials over the real numbers of degree 2 or less. W={p € P2 :p (3)=0} O True O Fale In the essay box below, if it is true, prove that W is closed under scalar multiplication. Otherwise, give an explantion why the statement is false. XDX HE Editor A-AIBIU S *** Styles Font Size Words:...