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The values listed below are waiting times in minutes) of customers at two different banks. Al Bank A customers enter a single
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a.
CONFIDENCE INTERVAL FOR STANDARD DEVIATION
ci = (n-1) s^2 / ᴪ^2 right < σ^2 < (n-1) s^2 / ᴪ^2 left
where,
s = standard deviation
ᴪ^2 right = (1 - confidence level)/2
ᴪ^2 left = 1 - ᴪ^2 right
n = sample size
since alpha =0.05
ᴪ^2 right = (1 - confidence level)/2 = (1 - 0.95)/2 = 0.05/2 = 0.025
ᴪ^2 left = 1 - ᴪ^2 right = 1 - 0.025 = 0.975
the two critical values ᴪ^2 left, ᴪ^2 right at 9 df are 19.68 , 2.7
s.d( s )=0.5754
sample size(n)=10
confidence interval for σ^2= [ 9 * 0.33/19.68 < σ^2 < 9 * 0.33/2.7 ]
= [ 2.98/19.68 < σ^2 < 2.98/2.7 ]
[ 0.15 < σ^2 < 1.05 ]
and confidence interval for σ = sqrt(lower) < σ < sqrt(upper)
= [ sqrt (0.15) < σ < sqrt(1.05), ]
= [ 0.39 < σ < 1.02 ]
95% confidence interval for population standard deviation at Bank A
b.
CONFIDENCE INTERVAL FOR STANDARD DEVIATION
ci = (n-1) s^2 / ᴪ^2 right < σ^2 < (n-1) s^2 / ᴪ^2 left
where,
s = standard deviation
ᴪ^2 right = (1 - confidence level)/2
ᴪ^2 left = 1 - ᴪ^2 right
n = sample size
since alpha =0.05
ᴪ^2 right = (1 - confidence level)/2 = (1 - 0.95)/2 = 0.05/2 = 0.025
ᴪ^2 left = 1 - ᴪ^2 right = 1 - 0.025 = 0.975
the two critical values ᴪ^2 left, ᴪ^2 right at 9 df are 19.68 , 2.7
s.d( s )=1.8394
sample size(n)=10
confidence interval for σ^2= [ 9 * 3.38/19.68 < σ^2 < 9 * 3.38/2.7 ]
= [ 30.45/19.68 < σ^2 < 30.45/2.7 ]
[ 1.55 < σ^2 < 10.68 ]
and confidence interval for σ = sqrt(lower) < σ < sqrt(upper)
= [ sqrt (1.55) < σ < sqrt(10.68), ]
= [ 1.24 < σ < 3.27 ]
95% confidence interval for population standard deviation at Bank B

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