Question

The figure below shows a resistor network. R2 ww R R3 RA V The values of the components are as follows: • R = 4.722 • R2 = 6.81 2 • R3 = 8.83 2 • R = 9.56 12 . V = 14.70 Volts

Answer 1

Date Ibi EI RI I3 R3 RAI 114 Ict R4 Be Given R, = 4.72 e, R2 = 6-812, R3=8.832 R4 = 9.562 & v=14:20 6.81 x 8.83 RA= R3ll R2 = R2 R3 R2+R3 - = 3.842 6-81 +8,83 ZYRA=3.84 22 RB = RATRI = 3.84 +4+72 2=8.562 DIRB = 8.562 & Rc = RBIR4 = R4 RB RatRB 9.56x8.56 9.5b+ 8.50 = 4.522 => 1 Rc = 4:52 for currents I c = IB + I4 IBI, Ic = I2+ Iz

Ica 14.90 4052 4 -3.252 A Ic-3.252 A $ Nc = IC Re - 3.252x4'52 = 14.70 V Duc - 14.700 9.56 x 3.252 A = 1.716 A IR = R4 x Ic x Ic = Rut RB 18 = 1716 A 9.56+8.56 .. VBIB RB =1-716 *8.58 -14.70 (VB=14:20 V of IAZIB 21716A >>IA 1.716 A .: VAIA RA - 1.71643.84 6.59 v NA=6:59 v I, IB =) I, 1*716A of Vi - I, Ry = p 216 x 4.72 V-8.1 V Ne 8.10 V T & P, I, = 1.716x 8.1 13.9W -P=13.9 W 8.83 = x 1.716 A 8.83+ 6.87 12 R3 XIA =) Rat R3

I 20.969 A .!. 12. I 2. R2 0.969 x 681 6.60 V 126.60 V - 6.39 W c. P₂ = I2 V₂ -0.969 x 616 P2 = 6.39 w + Iz = IA- I2 31716 – 0.969 A 30747 A I3 = 0.747 A > z= I3 R3 = 0.747X8.83 Y - 6.60v 136.60 V .. P₂ = I3V3 = 0.74786.6 W 4.93w h = 4.93 W of 142 Ic-IB Ic-IB = 3.252–1716 A = 1.536 A I4 = 1.536A V4 = I4R4 = 1.5369.56 N = 14.70 v V2=14.30 V & P4 = V4 I4 = 14.70x1.536 W = 22:58 W Py = 22.58 W

R62) Y CV) ICA) B (W) R 4.72 8.10 1716 13.9 R2 6.81 6 60 0969 6.39 R3 8.83 60 60 0,747 4.93 R4 9.56 14:20 1536 22:58 RA 3.84 6.59 1:716 RB 8.56 14.70 1716 14.70 4:52 Re 3.252