Question

in a clinical trial 27 out of 854 patients in a condrug dalycomed of the symptoms, pois now on coming company is there will conclude more than 25 of this drugs users cance fuke symptoms as a side effect at the 01 of 2 of the poor and the same the requests for testing the hypothes wasted Decause (-) Desme Round to one capace as needed What are the null and alterative hypotheses? Ho VESH (Typenlegers or dem Do not round Find the best ( Round to two decapaces as need Find the P Round to the decimal places as needed Choose the correct conclusion below O A Since vedo not receptes and conclude that there is not uncent evidence to OB. Since vedenied the potess and conclude the video more than 29 of the wees OC Since the walls and condemnat there is not suficient de ce more expence moms OD. Since the wypothes and conclude that there is sufficient evidence at more than the

Answer 1

1.

np0(1-p0) = 854 * 0.029 * (1 - 0.029) = 24.04779

Because np0(1-p0) = 24.0 > 10, the sample size is less than 5% of the population size, and sample can be assumed to be a random sample, the requirements for testing the hypothesis are satisfied.

H0: p = 0.029 versus H1: p > 0.029

Standard error of sample proportion, SE = sqrt(p0(1-p0)/n) = sqrt(0.029 * (1-0.029)/854) = 0.005742218

Sample proportion, p = 27/854 = 0.03161593

Test statistic , z = (p - p0) / SE = (0.03161593 - 0.029) / 0.005742218 = 0.46

P-value = P(z > 0.46) = 0.323

A. Since p-value > alpha, do not reject the null hypothesis.

2.

(a)

H0: $\mu$ = 35.1 million shares

H1: $\mu$ $\ne$ 35.1 million shares

(b)

Standard error of mean, SE = s / sqrt(n) = 14.5 / sqrt(30) = 2.6473

Degree of freedom = n-1 = 30-1 = 29

Critical t value at df = 29 and 95% confidence interval is  2.045

Lower Bound = 26.5 - 2.045 * 2.6473 =  21.086

Upper Bound = 26.5 - 2.045 * 2.6473 =  31.914

(c)

Since the value 35.1 million shares does not lie in the interval,

D. Reject the null hypothesis because $\mu$ = 35.1 million shares does not fall in the confidence interval.