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For a flow of 100mol / h of propane gas, what is the theoretical air that...

For a flow of 100mol / h of propane gas, what is the theoretical air that should be supplied in mol / h?

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Answer #1

Solution: The combustion reaction of propane is given as follows:

C3H8 + 5O2 -----> 3CO2 + 4H2O

From the equation, it can be seen that 1 mole of propane requires 5 moles of oxygen for complete combustion.

So, 100 mol/h of propane will need 500 mol/h of oxygen for complete combustion.

But, air has only 21% oxygen.

So,  theoretical air that should be supplied in mol/h for 100 mol/h of propane = 500/0.21 = 2380.95 mol/h of air.

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