For a flow of 100mol / h of propane gas, what is the theoretical air that should be supplied in mol / h?
Solution: The combustion reaction of propane is given as follows:
C3H8 + 5O2 -----> 3CO2 + 4H2O
From the equation, it can be seen that 1 mole of propane requires 5 moles of oxygen for complete combustion.
So, 100 mol/h of propane will need 500 mol/h of oxygen for complete combustion.
But, air has only 21% oxygen.
So, theoretical air that should be supplied in mol/h for 100 mol/h of propane = 500/0.21 = 2380.95 mol/h of air.
For a flow of 100mol / h of propane gas, what is the theoretical air that...
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