Question

Question 17 0/8 pts Propane (C3H3) burns completely with 230% of theoretical air entering at 74°F, 1 atm, 50% relative humidity. The dry air component can be modeled as 21% O2 and 79% N2 on a molar basis. The combustion products leave at 1 atm. Determine the dew point temperature of the products, in °F. (There is a +/-5% tolerance) 61.35

Answer 1

$0): The metical an - 230°. Reaction ÿ as ... chemical follows: C +(3.30) + [q,+ 3.76 Ny] => 3 [00,]+4 [H0]+(3.30) Z(0,+ (3. 30)(3.7)[N] Z = 3+4= 3+2=5 SH+ (3-30) (5) (0+ 3.76 M) =3[00,]+ 4 [H0] + 16.50 +(3:30)/3.705 [N] Cg Mg + 16.5 (0+ 3.76 1,7 => 3 [co] + 4 [HO] a 16.5102] + 62.0454] Norotal Notal 3+ 4+16.5 + 62.04 = 95.54 65.54 PO = (10.32 kPa) Pro = 4.7379 kPa T sew.point o = 31.96°C point = 'sat@ 4.74 kPa [: 31.96*9 +237 = 89.53't Dew point Temperature = 89.93°F ::