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At the instant represented, the velocity of point A of the 2.06-m bar is 3.1 m/s to the right. Determine the speed Va of poin

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solution : Velocity Analysis by Instantaneous Center Method: o [ Instantaneous Center) 590 k0.52 590 F 2,06m en ABCD: CI = BCthen : Given: AB= 2.06m 0 5901 Angle: LOBA = 31 +0 = 31° +7° [ZOBA 380] LOAB: 90-0 = 90-7 (2018- 834 380 83 w VA By sine Rule(VB = 5 m/ see > where, W = Angular velocity of the bar AB. VB 5 m/sec 2.1 rad/ see Any W = csscanned with CamScannerAnswer question

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