Question)
D = (0, 3) and E = (3, -1)
You need to find the equation of line that is perpendicular bisector of segment DE.
Perpendicular bisector of segment DE must pass through mid-point of segment DE.
Let B be the point which is mid-point of segment DE.
Using mid-point formula:
Let y = mx + c be the equation of line that is perpendicular bisector of segment DE.
Slope of segment DE =
m = -4/3
Also y = mx + c passes through point (3/2 ,1)
Therefore, equation of line that is perpendicular bisector of segment DE is
b)
Any point A on line y = -(4/3)x + 3 will form a triangle DEA such that DE = EA. But A cannot be coordinates of mid-point of line DE i.e B.
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