Question

A circle has the equation x + y -X-6y + 9 = 0. Graph the circle using the center (h.k) and radius r. Find the intercepts, if any, of the graph. Use the graphing tool to graph the circle. 1. Click to enlarge graph What are the intercepts? Select the correct choice below and fill in any answer boxes within your choice. A. The intercept(s) is/are (Type an ordered pair. Use a comma to separate answers as needed.). OB. There are no intercepts

Answer 1

solution - Civen, Given , circle has the equation x² + y² - x-64+ 9 =0 We have to compare this equation to the circle of radius xl and centre (hk). Q-) + Ly -kj? - © het convert the equation in this form. 2² xx 1 x 2 + 1 - 2 + y² -6y + 9 =0 (x - 2)2 + (y - 3)² = (± 1 2 By comparing equation ③ 4 ③ we have (r = – and (hik) = (213) Now, for finding intercept - - put x=0 in equation ③ - o + y 2 - 0 - 64+9 =0 (4-3) = 0 y=3 (x,y) = (0,3) y - intercept I (Touching point yaxis at y -axis le tangent) (013) hik)a (413) 2 + 1 I+II inox-axis for 2 3 -27 - t correct as circle option (B) is touches y-axis only.