Question

16 For the quadratic function f(x) = -x2 - 8x, answer parts (a) through (c) (a) Graph the quadratic function by determining whether its graph opens up or down and by finding its vertex, axis of symmetry, y-intercept, and X-intercepts, if any. Does the graph off open up or down? 12 8- up Odown 2015 12 118 12 16 What are the coordinates of the vertex? The vertex of the parabola is (Type an ordered pair. Use integers or fractions for any numbers in the expression.) What is equation of the axis of symmetry? The axis of symmetry is (Type an equation.) What is/are the x-intercept(s)? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The x-intercept(s) is/are (Type an integer or a decimal. Use a comma to separate answers as needed.) OB. There are no X-intercepts. What is the y-intercept? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The y-intercept is (Type an integer or a decimal.) B. There is no y-intercept. Use the graphing tool to graph the function. Click to enlarge graph (b) Determine the domain and the range of the function. The domain offis (Type your answer in interval notation.) The range of fis

Answer 1

Des Giveu quadraha Junction fin) = -n2-8n (a) fou a-12_8n =) y = -212-8n ① ince of co-efferent of nen negalve graph fon) will open down ophon "down" is correct (1 ya-02-8n =-(0²+8n) = - {( x + 2)2_16} y = -(4+4)² +16 a (9-16) - (2+4) verten of parabola is ((-4, 16) of Synutryn=-4 To get x-mercept Rey put yo on anis 25 0 = -n2-8n =) - n(n+8) zo 2) 7201 - 8 s-intercepts are 18,0] To get y. im tercept, put y = -0² - 8xo 2 y=0 y-inlercep in y=0 So feare Ino y. intercept uzo

verten arus of syneby (-4,16 16 (2+ 10 2 1 -10 -2 2 4 6 & (0 -2 dehned for all real numbe (6) domain since funchon in domain ( -2, 0) Range of function & value of fruchon varies from to 16 . Range = (-2, 16 (c) fuuchen and function decreanny ✓ increasing on the interval (-2,-4) on the interval (-4,2).