Question

please help me with this question. it has parts a through c.

For the quadratic function f(x) = x2 + 4x - 5 answer parts (a) through (c). (a) Graph the quadratic function by determining whether its graph opens up or down and by finding its vertex, axis of symmetry, y-intercept, and x-intercepts, if any. Does the graph off open up or down? 12 8- Oup down 4 -20 16.12 8 20 What are the coordinates of the vertex? The vertex of the parabola is (Type an ordered pair Use integers or fractions for any numbers in the expression) What is the equation of the axis of symmetry? -12

b:

c:

Thanks for your generous help. please provide me the answers for this question

Answer 1

Given quadratic function for=x76x-5 For fx=axt bare: It axo, then fx open upward aco, then fox open doconward Here a=170 Graph of f is open up: Vertex of far= a (x-2)²tk is (h, k) f(x)= x²+4075 = x2(2)(x) +2²-2²-5 = (x+2)-4-5 (x+2) = 9 . The vertex of parabola &s (-2,-9). → for fox)= axbx+c, axis of symmetoy is daba .. Equation of axis of symmeby is x = -4 fol = x=-2 x-intercepts are the points where foto x3742-5=0 G+2)_q=0 a+2)=93x+2=3 tara 04+2 = -3 2+2=3 x=-5 2=) The x-intercepts are at woh-5, I} y-intercept is a point where a=0 fo=0²-400)-5 fol=5 ... The y-intercopt is at BE1-5}

Graph: fx) uu 3 3 u -u 8 701 Vertex -- Range Domain is all possible a values t gooph Hunction is all possible y values of graphlfunction The domain of f is (-00,00) range of f is (-9,0) The function is increasing The function is decreasing on (-9,00 on (-00-9)