Question

Problem 3 - Rigid Body Kinematics (10 pts) Roller B of the linkage has a velocity of 0.75 m/s to the right as the angle o passes 60°. Locate the instantaneous center of zero velocity for bar AB and determine its angular velocity WAB: Equations you may need: B Law of sines sin A b sin B a с α 360 mm 360 mm A C D Law of cosines b BO 0.75 m/s c2 = a2 + b2 – 2ab cos C c2 = a² + b2 + 2ab cos D

Answer 1

Anet 0 = 60° Wa Ba? 360 mm, 360 mm DO > 0.75ml Instantaneous censcs of uro velocity = ? - ? (Point () С. using sine law in D ABC, 1200 AB BC Sin A Sinc 360 36 60 C AB- 360mm 0 2) BC sin 120° AB sin 30" B3 623-5 mm = BC=360 (2) 2 Point (y fixed Therefore, (WAB as VB Вс (w = 3 ) 0.75ml WAB 750 mmis 623-5 mm counter Long -- 1:20 rad's 1,20 sadls (clockwise direction 2. (Anticlockwise)