Question

Problem 1 - Particle Kinematics (10 pts) To increase his speed, the water skier A cuts across the wake of the tow boat B, which has a velocity of VB = 60 km/h. at the istantant when 0 = 30°, the actual path of the skier makes an angle B = 50° with the tow rope. For this position determine the velocity VA of the skier and the value of ė. Equations you may need: B 10 m Law of sines sin A b sin B a с a C D A ''B Law of cosines b B c? = a² + b2 – 2ab cos C c? = a2 + b2 + 2ab cos D

Answer 1

1 kmph = 5/18 m/s

Giveni Ve = 60 km/h, 0 = 30° , ß, so 0 = 30° , ß = 50 , r = 10m To find! DA V or w Angular velocity) VB ces o 60 x cos 30°= 5), 96 km/h А o + JB B VA V" 52.96 cas cosso IVA = 80.84 km/h I'= VA sinß = 80.84 x gin 50° = 61.92 Km/hr or 17.2 m/s P = 0 = 17.2 Lo = w = 1.72 rad/s r D