The number of grams of aluminum hydroxide that will form when
5.22 moles of aluminum sulfate react with sodium hydroxide
according to the reaction
Al 2 (SO 4) 3 + 6 NaOH → 2 Al(OH)
3 + 3 Na 2SO 4 is:
204 grams |
||
134 grams |
||
814 grams |
||
33.5 grams |
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