How many grans of aluminum hydroxide will react with 75.0mL of
0.319M of sulfuric acid solution?Homework Answers
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How many grans of aluminum hydroxide will react with 75.0mL of 0.319M of sulfuric acid solution? 3. Aluminum hydroxi...
if 25.26 mL of a 0.125 M solution of aluminum hydroxide reacts exactly with 22.00 mL of a sulfuric acid solution, what...
if 25.26 mL of a 0.125 M solution of aluminum hydroxide reacts
exactly with 22.00 mL of a sulfuric acid solution, what is the
molarity of the sulfuric acid solution?
3H2SO4(aq) + 2Al(OH)3(aq) → Al2(SO4)3(aq) + 6H20(1) a) How many grams of aluminum hydroxide will react with 75,0 mL of 0.319 M sulfuric acid solution? moles of H₂SO4 0.3198 0.075 0.0239 moles 3 moles of H2Soy requires 2 moles Al(OH)3 0.023a moles of the 504 - 2xo.0239 moles of Al(OH)₃...
4. Describe (in detail) using both words and calculations how you would prepare 2.0 L of...
4. Describe (in detail) using both words and calculations how you would prepare 2.0 L of a 0.100 M KCl solution from a 5.5 M stock KCl solution. (2 pt) 5. Aluminum hydroxide will react with sulfuric acid to yield aluminum sulfate and water according to the equation below: (4 pt) 3H2SO4(aq) + 2Al(OH)3(aq) → Al(SO4)3(aq) + 6H20(1) a) How many grams of aluminum hydroxide will react with 75,0 mL of 0.319 M sulfuric acid solution? b) If 25.26 mL...
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) a. Which reagent i...
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) a. Which reagent is the limiting reactant when 0.450 mol Al(OH)3 and 0.450 mol H2SO4 are allowed to react? b. How many moles of Al2(SO4)3 can form under these conditions? c. How many moles of the excess reactant remain after the completion of the reaction?
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when...
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when 0.550 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react? Al2(SO4)3(aq) Al(OH)3(s) H2O(l) H2SO4(aq)
3. Aluminum chloride reacts with sulfuric acid to form aluminum sulfate and hydrochloric acid according to...
3. Aluminum chloride reacts with sulfuric acid to form aluminum sulfate and hydrochloric acid according to the balanced chemical equation below. 2A1C13(aq) + 3H2SO4(aq) → Al2(SO4)3(aq) + 6HCl(aq) 133.340 g/mol 98.079 g/mol 342.150 g/mol 36.460 g/mol Molar Masses: a) How many grams of sulfuric acid react with 25.0 grams of aluminum chloride? b) What is the theoretical yield of HCl if sulfuric acid is in excess?
For the reaction 2Al+3H2SO4⟶3H2+Al2(SO4)32Al+3H2SO4⟶3H2+Al2(SO4)3 how many grams of sulfuric acid, H2SO4, are needed to react completely...
For the reaction 2Al+3H2SO4⟶3H2+Al2(SO4)32Al+3H2SO4⟶3H2+Al2(SO4)3 how many grams of sulfuric acid, H2SO4, are needed to react completely with 72.1 g of aluminum, Al?
Aluminum metal reacts with sulfuric acid according to the following equation: 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(s)...
Aluminum metal reacts with sulfuric acid according to the following equation: 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(s) + 3H2(g) If 12.9 g of aluminum reacts with excess sulfuric acid, and 62.4 g of Al2(SO4)3 are collected, what is the percent yield of Al2(SO4)3?
Sulfuric acid dissolves aluminum metal according to the following reaction: 2Al(s)+3H2SO4(aq)-----=Al2(SO4)3(aq)+3H2(g) Suppose you wanted to dissolve...
Sulfuric acid dissolves aluminum metal according to the following reaction: 2Al(s)+3H2SO4(aq)-----=Al2(SO4)3(aq)+3H2(g) Suppose you wanted to dissolve an aluminum block with a mass of 14.9g . What minimum mass of H2SO4 would you need? What mass of H2 gas would be produced by the complete reaction of the aluminum block? Express your answer in grams.
2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many grams of Al(OH)3...
2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many grams of Al(OH)3 would be consumed by the reaction of 3.8 moles of H2SO4 ?
If 3.40 g of aluminum hydroxide reacts with 1.25 g of sulfuric acid, what is the...
If 3.40 g of aluminum hydroxide reacts with 1.25 g of sulfuric acid, what is the mass of water produced? Al(OH)3(s)+H2SO4(l)→Al2(SO4)3(aq)+H2O(l)
if 25.26 mL of a 0.125 M solution of aluminum hydroxide reacts
exactly with 22.00 mL of a sulfuric acid solution, what is the
molarity of the sulfuric acid solution?
3H2SO4(aq) + 2Al(OH)3(aq) → Al2(SO4)3(aq) + 6H20(1) a) How many grams of aluminum hydroxide will react with 75,0 mL of 0.319 M sulfuric acid solution? moles of H₂SO4 0.3198 0.075 0.0239 moles 3 moles of H2Soy requires 2 moles Al(OH)3 0.023a moles of the 504 - 2xo.0239 moles of Al(OH)₃...
4. Describe (in detail) using both words and calculations how you would prepare 2.0 L of a 0.100 M KCl solution from a 5.5 M stock KCl solution. (2 pt) 5. Aluminum hydroxide will react with sulfuric acid to yield aluminum sulfate and water according to the equation below: (4 pt) 3H2SO4(aq) + 2Al(OH)3(aq) → Al(SO4)3(aq) + 6H20(1) a) How many grams of aluminum hydroxide will react with 75,0 mL of 0.319 M sulfuric acid solution? b) If 25.26 mL...
3. Aluminum chloride reacts with sulfuric acid to form aluminum sulfate and hydrochloric acid according to the balanced chemical equation below. 2A1C13(aq) + 3H2SO4(aq) → Al2(SO4)3(aq) + 6HCl(aq) 133.340 g/mol 98.079 g/mol 342.150 g/mol 36.460 g/mol Molar Masses: a) How many grams of sulfuric acid react with 25.0 grams of aluminum chloride? b) What is the theoretical yield of HCl if sulfuric acid is in excess?
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