2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many grams of Al(OH)3...

Question

Question

2Al(OH)₃ + 3H₂SO₄ -----> Al₂(SO₄)₃ + 6H₂O

In the above reaction, how many grams of Al(OH)₃ would be consumed by the reaction of 3.8 moles of H₂SO₄ ?

Answer 1

Answer #1

Answer

197.6g

Explanation

2Al(OH)3 + 3H2SO4 ------> Al2(SO4)3 + 6H2O

From the balanced equation , we know that 3moles of H2SO4 reacts with 2moles of Al(OH)3

Therefore

Number of moles of Al(OH)3 consumed = (2/3)×3.8mol = 2.533mol

mass = number of moles × molar mass

mass of Al(OH)3 would be consumed = 2.533mol × 78.01g/mol = 197.6g

Answer 2

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