We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
Consider the reaction: 2 Al(OH)3 + 3 H2SO4 à Al2(SO4)3 + 6H2O. How many grams of...
2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many grams of Al(OH)3 would be consumed by the reaction of 3.8 moles of H2SO4 ?
2 Al(OH)3 + 3 H2SO4 + 6H30+ Al2(SO4)3 How many grams of Al(OH)3 are required to completely convert 15.943 g of H2SO4 into Al2(SO4)3?
2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many moles of Al2(SO4)3 would be produced by the reaction of 3.8 moles of H2SO4 ?
For the reaction 2Al+3H2SO4⟶3H2+Al2(SO4)32Al+3H2SO4⟶3H2+Al2(SO4)3 how many grams of sulfuric acid, H2SO4, are needed to react completely with 72.1 g of aluminum, Al?
Mixing 39.0g of Al(OH)3 with an excess of H2SO4 we produce Al2(SO4)3. Using the following equation answer the following: I have already balanced the equation from Al(OH)3+H2SO4---->Al2(SO4)3+H2O 2Al(OH)3 + 3H2504 → Al2(SO4)3 + 6H2O a. Determine and circle the limiting reagent for A12(SO4)3 (show all its calculations). b. Determine and circle the yielding theory for Al2(S04)3 (show all its calculations). of Al2(SO4)3 (show all its Determine the % of yield, if the experimental yield is 73.25 calculations). c.
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) a. Which reagent is the limiting reactant when 0.450 mol Al(OH)3 and 0.450 mol H2SO4 are allowed to react? b. How many moles of Al2(SO4)3 can form under these conditions? c. How many moles of the excess reactant remain after the completion of the reaction?
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when 0.550 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react? Al2(SO4)3(aq) Al(OH)3(s) H2O(l) H2SO4(aq)
10. For the equation 2 H2SO4 + 2 Al → 2 H2 + Al2(SO4)3, suppose you wished to prepare 28.7 grams of H2. How many grams of H2SO4 and of Al would you require so that all of the H2SO4 and Al were combined?
Sulfuric acid (H2SO4) dissolves Aluminum metal according to the reaction: 2 Al(s)+ 3 H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g) Suppose you want to dissolve an Aluminum block with a mass of 15.2 g. What minimum mass of H2SO4 (in g) do you need? What mass of H2 gas (in g) can the complete reaction of the aluminum block produce? Please Show Work
The following equation can be classified as what type(s) of reaction(s)? Al(OH)3(aq)+H2SO4(aq)~ Al2(SO4)3(s)+H2O(l) balance the equation.