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2 Al(OH)3 + 3 H2SO4 + 6H30+ Al2(SO4)3 How many grams of Al(OH)3 are required to...
Consider the reaction: 2 Al(OH)3 + 3 H2SO4 à Al2(SO4)3 + 6H2O. How many grams of Al2(SO4)3 are generated when 152 g of H2SO4 reacts? Show Work on Scratch Paper! O 530.g of Al2(SO4)3 O 1590 g of Al2(SO4)3 177 g of Al2(SO4)3 43.6 g of Al2(SO4)3 131 g of Al2(SO4)3
For the reaction 2Al+3H2SO4⟶3H2+Al2(SO4)32Al+3H2SO4⟶3H2+Al2(SO4)3 how many grams of sulfuric acid, H2SO4, are needed to react completely with 72.1 g of aluminum, Al?
2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many grams of Al(OH)3 would be consumed by the reaction of 3.8 moles of H2SO4 ?
10. For the equation 2 H2SO4 + 2 Al → 2 H2 + Al2(SO4)3, suppose you wished to prepare 28.7 grams of H2. How many grams of H2SO4 and of Al would you require so that all of the H2SO4 and Al were combined?
Mixing 39.0g of Al(OH)3 with an excess of H2SO4 we produce Al2(SO4)3. Using the following equation answer the following: I have already balanced the equation from Al(OH)3+H2SO4---->Al2(SO4)3+H2O 2Al(OH)3 + 3H2504 → Al2(SO4)3 + 6H2O a. Determine and circle the limiting reagent for A12(SO4)3 (show all its calculations). b. Determine and circle the yielding theory for Al2(S04)3 (show all its calculations). of Al2(SO4)3 (show all its Determine the % of yield, if the experimental yield is 73.25 calculations). c.
2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many moles of Al2(SO4)3 would be produced by the reaction of 3.8 moles of H2SO4 ?
a) How many mol of Al2(SO4)3 are required to make 40 mL of a 0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? c) What mass of Al2(SO4)3 is required to make 40 mL of a 0.050 M...
a) How many moles of Al2(SO4)3 are required to make 44 mL of a 0.090 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 44 mL of...
a) How many moles of Al2(SO4)3 are required to make 55 mL of a 0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 55 mL of...
a) How many moles of Al2(SO4)3 are required to make 43 mL of a 0.060 M Al2(So4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(S04)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 43 mL of...