Question

2Al+3H2SO4⟶3H2+Al2(SO4)3

how many moles of hydrogen will be produced from 17.6 g of aluminum?

Answer 1

Answer -

Given,

Mass of Aluminium = 17.6 g

Molar Mass of Aluminium = 26.98 g/mol

Moles of Hydrogen produced = ?

2 Al + 3 H2SO4 $\rightarrow$ 3 H2 + Al2(SO4)3 [BALANCED]

We know that,

Moles = Mass / Molar Molar Mass

So,

Moles of Al = 17.6 g / 26.98 g/mol

Moles of Al = 0.652 mol

Now,

Using Stiochiometry, it can be analyzed that for 2 moles of Al, 3 moles of Hydrogen are produced. i.e.

Moles of Hydrogen produced = (3/2) * Moles of Al

Moles of Hydrogen produced = (3/2) * 0.652 mol

Moles of Hydrogen produced = 0.978 mol [ANSWER]