Question

I decided to try out a problem using a wedding reception dinner, where the probability that there are vegetarians. Assume a .5 chance of having a vegetarian.

1. Examine the probability for a wedding reception that has 25 guests in the wedding party with exactly 10 vegetarians
2. Next, look at the probability that they have more than 10 vegetarians
3. Lastly, look at the probability that they have at most 10 vegetarians.

Answer 1

Let vegetarians a) P(x= 10) 25 x= No. of Xu Binomial In, p) = 25, P=0.5 q = 1-P 0.5 P(x=x) = nex p q x Co (0.5) (0.5) b) P(x>10) 1- P(x < 10) [ P(x) -- [Plx=0) +P/x=1) + P(x-2) + - +P(x=10) J = 1- [o +0 +0+0 +0.0004 +0.0016 +0.0053 +0.0143 +0.0322 +0.0609+.0.0974] x = 0,1 – – – , n 15 30.0974 16 2) X=D 2 ) - 0,2121 = 0,7879 16 c) P(x410) = P(x) x=0 [from part b 11 02121