(a)
For continuous distribution function,
F(a) = 0
=> ln(a) = 0
=> a = 1
and , F(b) = 1
ln(b) = 1
b = e where e is exp(1)
(b)
P(X > 2) = 1 - P(X 2)
= 1 - F(2)
= 1 - ln(2) (as, 1 < 2 < e)
= 1 - 0.6931472
= 0.3068528
(c)
The probability density function of X is,
for 1 < x < e
else f(x) = 0
(d)
= 2.718282 - 1
= 1.718282
Please help with this question. 12. (15 points) Let X be a continuous random variable with...
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