Question

Question 9 (4 points) The rate of effusion of NH3 is 2.40 mole/min. What would be the rate of effusion of H2 under the same conditions? 7.00 O 0.28 2.40 0.82 2.04

Answer 1

If a gas is kept in a container and made to escape out of a hole whose diameter is comparable to the mean free parh, then the process of escaping out is known as effusion.

Effusion for a gas is inversely proportional to the square root of mass of particles of the gas or molar mass of the gas

The problem is solved in the picture attached below :

14 + 3 =17 R = 2.40 mol/min rate R Moss of NH3 Effusion Mass of Hycleogen Effusion rate R 1 52 R2 R, IGHE 2 R2 x 2.40 = 6.99 V 7.0 Rate of Effusion of H₂ 27:00

11)All the salts given in the problem are ionizable which means they can dissociate into ions.to find the maximum concentration of Na+ ions , write the dissociation equation.

Molarity of Na+ ions will be the molarity of salt multiplied by number of ions of Na+.

The problem is solved in the picture attached below.

& Nach Nat 0.20m + a 0:20M O: 20 M Naz Soy 2Na+ + SO4 O 15 M 0 30M OISM 3 Nat Naz pou 0:090 + Pout 0.090 0.270 t Na Na C₂H₂O2 + + CH 302- 0:10 Jo.10 Oilo Highest concentration of sodium ion in 0.15M Nasoy 0.30 M Answee.

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