Solution 11:-
Correct option - B
Option A is not valid as it includes all the strings of 0 and 1 and kleen clousre makes it all possible combinations which is uncountable. Option C is invalid as b , c belongs to set of intergers and there can be many intergers which follows a=b+c/2. Since option A,C is invalid so option D , E are invalid. Subset of {0,1}* can be countable so option B is valid.
Solution 12:-
Correct option - E
Option A is invalid as it is turning recognizable. Option C is
invalid as for the stated language it is turning
recognizable.
Option B , D are correct as the stated in option D is an example of
Turing unrecognizable and number of all possible Language is
included in the power set and for Turing unrecognizable the power
set of the language is greater than set of Turing machine.
11. (1 point) Which of the following sets are countable? A. {0,1}" B. {LL C{0,1}} C....
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