Question

Determine the Force in member AE and indicate if the member is in compression or tension. (560 KN 220 KN 860 KN)

Answer 1

Anu 13. Space Truss Determine the Force in member AE and indicate if the member is in compression or tension. COLO/4) AE 560 KN 220 KN & componcret of (11-o) FAEx= 11m 860 KN 4m AL D (11,-5,0) 112+ 6532442 5m X FAG 8.8624 FAG 560 FAB Joint A 220KN a R FAE 860 a FAC Efn=0) - 220 + Ft Ex co -220 + 0.864 FAE =0, FAE = 254.56 Kn Tension

Let us consider an inclined section in a frame X 220 KN In Y-Z plane A 7 length AD B - E G Y X Cors .:: IAD) 14+52 6.403m. Component of forcelin member AE) in X-direction F sinol F x 11 Fr6.403 0.86421 Apply equilibrium equation at joint A E fx 0.86 42 F 22o F 254.557 KN. force in member A E = 2.1 K in Tensioni CSScanned with CamScanner
​​​​​Please upvote if you like the solution, Thank you.!

Answer 2

Answer 3

Anu 13. Space Truss Determine the Force in member AE and indicate if the member is in compression or tension. COLO/4) AE 560 KN 220 KN & componcret of (11-o) FAEx= 11m 860 KN 4m AL D (11,-5,0) 112+ 6532442 5m X FAG 8.8624 FAG 560 FAB Joint A 220KN a R FAE 860 a FAC Efn=0) - 220 + Ft Ex co -220 + 0.864 FAE =0, FAE = 254.56 Kn Tension