Question

Problem 3 - Electric force and Electric field A charge Q1 = +9uC is located at the origin and a second charge Q2 = -4°C is placed at x = 8 m. a) [6 points) What will be the force (magnitude and direction) if you place a +16 C charge midway between the Qi and Q2? lu = 10-6, Coulomb's constant k = 9.0 x 10°N • m2/C2 b) [7 points] Calculate the net electric field (magnitude and direction) at x = 10 m due to the two charges Qi and Q2 given above. What is the force on an electron if it is placed at this point (i.e. x = 10 m)? electron charge = -e = 1.602 x 10-19C. c) [7 points) Find the point on the x-axis where the electric field is zero.

Answer 1

а) а, Чc :) Ө, – Чрс 1 Og 16с. Now , га , б, в, F 6, 8, 43 2 к- Чm -жЧm —— k sm Force в) a due to ay е, а у 9 —12 ах 10 х Чr 16 х 10 s'. і E ө, ө, Чл. 16 -3 л У Гале, 63 ÎN 8 x 10 1) Force 9, ., om G3 due to 9 - 12 У Чx 1 x 10 Чx 10 6, 8, Гб, , — : Что 2 М2 10 36 х 10 i N Fo6, Hence. - 3 36 х 10 і &1 курс 0.117 in 3 Forn

b) ēptempo QZP * * Oh, Now. Electric field at e due a to к — &m 9-2m K -10m Oni A Eur URE 9x10 x 9x10 1 81x105 Nc L 100 Europe 81 x 10 î N/c Electric field cat p due to Ora - E Q2 . 9 9x10 X 4 X10 Benuto (i). UK E 2 El -9x10² i Nic Hence, 31 E 81x10" 9x103 -3d - 8.19 X ID N/c X Force on the electron the election (F) q [-1.602* 16 109] [-2.196151 -22 13.12038 x 10

CO) Nowy Tu ТО , 1 в, N о + 2 Что х: чи % (- ) 2 а ве О, 4, Ө, ж-(-8) - -) + о к — $m 2 2. (1 - 2)? к X— ар Чи x 2 (1-Q)* Not possible 1 + х = 24 (4) ч. 9 (х - 29)( 5x - 24) *(a-3)2 и 2 possible. Не • х: 19 )