Ksp =[ Pb^+2][I^-]^2
Ecell = 0 - 0.0592/2 log(Pb^2+ Anode/Pb^2+ Cathode)
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Ksp =[ Pb^+2][I^-]^2
Ecell = 0 - 0.0592/2 log(Pb^2+ Anode/Pb^2+ Cathode)
Q3. Write and identify the...
Ecell = 0 - 0.0592/n log(Cu anode/Cu Cathode) Q2. Write and identify the oxidation and reduction...
Ecell = 0 - 0.0592/n log(Cu anode/Cu Cathode)
Q2. Write and identify the oxidation and reduction half-reactions for the Cu-Cu concentration cell. Combine these to give the overall reaction. Use the Nernst equation to calculate the theoretical value of Ecell and determine the percent error. Show all of your work. (4.0)
1. Fill in the blanks. Identify Half-Reactions Identify Reaction in Half Reaction (Oxidation or Reduction) Cathode...
1. Fill in the blanks. Identify Half-Reactions Identify Reaction in Half Reaction (Oxidation or Reduction) Cathode or Anode Cr2O72- + 14 H+ + 66 - 2 Cr + 7 H20 I Reduction Cathode [ Fet – Fet the xle Oxidation | Anode Give the balanced, overall redox equation between these half-reactions. 6fe tcr. O, 2- +14 tt lefest & zerst +7H.O
data collected Cu(NO3)2 | Zn(NO3)2 = 0.999 V Pb | 1.0 M Pb(NO3)2 || 1.0 M...
data collected
Cu(NO3)2 | Zn(NO3)2 = 0.999 V
Pb | 1.0 M Pb(NO3)2 || 1.0 M Zn(NO3)2 | Zn = 0.396 V
PART B: REDUCTION POTENTIALS 1. Report the measured cell potential for each galvanic cell and state which electrode corresponds to the cathode and which to the anode. 2. Given E = -0.76 V for the Zn/Zn half-cell, and your measured Ecell, calculate the reduction potential at the Cu and Pb electrodes and write the redox half- 6 reactions...
1. Identify the anode, the cathode, the reduced species and the oxidized species for the following...
1. Identify the anode, the cathode, the reduced species and the oxidized species for the following electrochemical cells. Write the half reactions for the anode and cathode, the overall reaction. Calculate the total cell potential. a) Fe (8)| Fe (aq) (0.2 M) || Ni” (aq) (0.1 M) | Ni(s) b) Zn (s) | Zn? (aq) (1.0 x 10' M)||Cl(aq)(0.3 M) CI, (g) (0.100 bar) Pt (S) c) Pb (s) Pb2(aq) (1.0 x 10ʻM) || Cu (aq) (1.0 x 10M) Cu...
Equation 18: (didnt mean to attach equation 15 oops) V-13 EXPERIMENT V: VOLTAIC CELLS, AND THE...
Equation 18: (didnt mean to attach equation 15 oops)
V-13 EXPERIMENT V: VOLTAIC CELLS, AND THE NERNST EQUATION PRELAB ASSIGNMENT (CONTINUED) 5. In aqueous solution Cu* ions are more stable than Cu ions because 2 Cu* (aq) + Cu2+ (aq) + Cu (s) (a) Give an oxidation half-cell reaction and a reduction half-cell reaction that can be combined to form this overall reaction. (0.5 marks) (b) Use Eq. 18 with your answer to (a) to calculate the theoretical K for...
An electrochemical cell uses Ni/Ni+2 and Cd/cd+2. a) Write the half reactions that will be spontaneous...
An electrochemical cell uses Ni/Ni+2 and Cd/cd+2. a) Write the half reactions that will be spontaneous for this cell. Oxidation- Reduction- b) Which metal is the anode and which is the cathode? anode cathode c) Calculate the emf (Ecell) for this cell. Eceu =
Chem 1212 Lab Report on electrochemistry Electrochemistry When electrons transfer between reaction components in a redox...
Chem 1212 Lab Report on electrochemistry
Electrochemistry When electrons transfer between reaction components in a redox reaction, we can harness the motion of the electrons to create a potential. Electrochemistry revolves around the separation of the two half-reactions in a redox reaction and establishing two different electrodes. This might involve physically separating the half-reactions or including a separator, such as a semi-permeable membrane or plastic dividers. With the reactions separated, the electrons will need to flow through the wire connecting...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
An electrochemical cell was designed in order to determine the solubility product constant, Ksp for PbCO3....
An electrochemical cell was designed in order to determine the solubility product constant, Ksp for PbCO3. The cell uses the half reactions shown below to produce the overall dissociation reaction. cathode reaction: anode reaction: overall reaction: PbCO3(s) + 2e — Pb(s) + Coz- (aq) Ph(s) — Pb2+ (aq) + 2 e- PbCO,(s) — Pb2+ (aq) + CO2 (aq) Which equality correctly represents the relationship between the equilibrium constant expression for the overall reaction and the solubility product constant for PbCO,?...
Questions Galvanic Cell Metal and Solution in Cathode Half-cell Cell Potential(v) Metal and Solution in Anode...
Questions
Galvanic Cell Metal and Solution in Cathode Half-cell Cell Potential(v) Metal and Solution in Anode Half-cell Black Wire (-) Red Wire (+) -2.370 Pt/H2 and Nitric Acid Mg and Magnesium Nitrate #1 -0.143 Pt/ H2 and Nitric Acid Pb and Lead (II) Nitrate #2 -0.249 Pt/ H2 and Nitric Acid #3 Ni and Nickel (II) Nitrate 다 5. Based on your information above write the half reactions occurring in each half-cell. Ensure you are writing the correct oxidation or...
Ecell = 0 - 0.0592/n log(Cu anode/Cu Cathode)
Q2. Write and identify the oxidation and reduction half-reactions for the Cu-Cu concentration cell. Combine these to give the overall reaction. Use the Nernst equation to calculate the theoretical value of Ecell and determine the percent error. Show all of your work. (4.0)
1. Fill in the blanks. Identify Half-Reactions Identify Reaction in Half Reaction (Oxidation or Reduction) Cathode or Anode Cr2O72- + 14 H+ + 66 - 2 Cr + 7 H20 I Reduction Cathode [ Fet – Fet the xle Oxidation | Anode Give the balanced, overall redox equation between these half-reactions. 6fe tcr. O, 2- +14 tt lefest & zerst +7H.O
data collected
Cu(NO3)2 | Zn(NO3)2 = 0.999 V
Pb | 1.0 M Pb(NO3)2 || 1.0 M Zn(NO3)2 | Zn = 0.396 V
PART B: REDUCTION POTENTIALS 1. Report the measured cell potential for each galvanic cell and state which electrode corresponds to the cathode and which to the anode. 2. Given E = -0.76 V for the Zn/Zn half-cell, and your measured Ecell, calculate the reduction potential at the Cu and Pb electrodes and write the redox half- 6 reactions...
1. Identify the anode, the cathode, the reduced species and the oxidized species for the following electrochemical cells. Write the half reactions for the anode and cathode, the overall reaction. Calculate the total cell potential. a) Fe (8)| Fe (aq) (0.2 M) || Ni” (aq) (0.1 M) | Ni(s) b) Zn (s) | Zn? (aq) (1.0 x 10' M)||Cl(aq)(0.3 M) CI, (g) (0.100 bar) Pt (S) c) Pb (s) Pb2(aq) (1.0 x 10ʻM) || Cu (aq) (1.0 x 10M) Cu...
Equation 18: (didnt mean to attach equation 15 oops)
V-13 EXPERIMENT V: VOLTAIC CELLS, AND THE NERNST EQUATION PRELAB ASSIGNMENT (CONTINUED) 5. In aqueous solution Cu* ions are more stable than Cu ions because 2 Cu* (aq) + Cu2+ (aq) + Cu (s) (a) Give an oxidation half-cell reaction and a reduction half-cell reaction that can be combined to form this overall reaction. (0.5 marks) (b) Use Eq. 18 with your answer to (a) to calculate the theoretical K for...
An electrochemical cell uses Ni/Ni+2 and Cd/cd+2. a) Write the half reactions that will be spontaneous for this cell. Oxidation- Reduction- b) Which metal is the anode and which is the cathode? anode cathode c) Calculate the emf (Ecell) for this cell. Eceu =
Chem 1212 Lab Report on electrochemistry
Electrochemistry When electrons transfer between reaction components in a redox reaction, we can harness the motion of the electrons to create a potential. Electrochemistry revolves around the separation of the two half-reactions in a redox reaction and establishing two different electrodes. This might involve physically separating the half-reactions or including a separator, such as a semi-permeable membrane or plastic dividers. With the reactions separated, the electrons will need to flow through the wire connecting...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
An electrochemical cell was designed in order to determine the solubility product constant, Ksp for PbCO3. The cell uses the half reactions shown below to produce the overall dissociation reaction. cathode reaction: anode reaction: overall reaction: PbCO3(s) + 2e — Pb(s) + Coz- (aq) Ph(s) — Pb2+ (aq) + 2 e- PbCO,(s) — Pb2+ (aq) + CO2 (aq) Which equality correctly represents the relationship between the equilibrium constant expression for the overall reaction and the solubility product constant for PbCO,?...
Questions
Galvanic Cell Metal and Solution in Cathode Half-cell Cell Potential(v) Metal and Solution in Anode Half-cell Black Wire (-) Red Wire (+) -2.370 Pt/H2 and Nitric Acid Mg and Magnesium Nitrate #1 -0.143 Pt/ H2 and Nitric Acid Pb and Lead (II) Nitrate #2 -0.249 Pt/ H2 and Nitric Acid #3 Ni and Nickel (II) Nitrate 다 5. Based on your information above write the half reactions occurring in each half-cell. Ensure you are writing the correct oxidation or...
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