Question

T(S) = s(4s + 5) 22s2 + 6 + 3 The closed loop transfer function above is derived from the ......... block diagram. R(S) + C(s) S S+1 + 2s 4

Answer 1

I solved all the 3 block diagram, But I'm not getting the transfer function which you have shown.

You can check my answer if you have any confusion about that.

RISD + Stir S 0 Parallel path Toop 10+ 10 = 20 parallel pathe loop: 20 SCS+12) 20 2010.2) S S($+12) +45 $ + 125 +45 S(5+12)

this is loop 20 20 ees) RIS R in series. 20 x 20 sl +165. - loop can be solved as. 400 s² + 165 All + 400 s² + 165 400 S+165 + 400 400 : T(S): CCS) RIS) 3+165+400. © 12 shifthing this node after RISD (79) pdraliet path.

ss So 1 +4 parallel path will be 45+ 1 S on series 45+) loop & series: loop will be ss 1 +53 3x I SS 3 ss 100P 45+1 S Ss 1a5s loop can be solved as. 8 CAS 70 () US+!) 145) (3) + 5(45+1) (1 +55) 1 + (45 +1) (3) S(1+55) 55645+1) 53²+ 135+3 SS(45+1) $(1+5520 + 3(45+12 55(4571) S² + S + 125+3

55(4541) 532 + 133+3 loop loop can be solved as, SS(45+1) 55²4 135 13 Sscusti), 53²+ 13543 55(45+1) 3² + 135 +3 + 205²55 T(S) 8 (205+5) 2532+ 185 +3 (3 125 U Rearrange the above block diaq tam as shown.

loop i s toop2 RIS) 25 St shifting this ned before 28. 125 7 25 loop ② can be solved as 145 S 1 ts. loop @ can be solved as It (st) S+2. S 25 S+2 parallel path. As we have two summing point together we can interchange them.

parallel path can be path can be solved as CS +25) 35 135 145 812 parallel path toop. parallel path can be solved as. 85 al S US + 25 +25. 852 (1+5) 352 + 2S CI+5) Clts ) 85² + 25 +28² (IAS) 55²+25 (145) loop can be solved as lit) + *4 (ste (5+2)+4 stb.

53²+25 Clas) (S+6) series can be solved as 58² +25 CS+)(3+6) 55² +25 (5 + 1) (346) loop can be solved as, 5 8² +25 (St 1 (ST6) + SS²+25 (5+1) CS 16) 5² + 25 (St 1 (s+6) +58425 S(SS+2) S²+75 +6 + SS²+25 TIS). S (55+2) 6² +95 +6.
I tried another way also but I'm getting same answer which I have shown above.

Thank You..