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{ Question 15 (3 points (Bonus) Given the following statemens, it may throw Input MismatchException. Adding exception handler

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Answer #1

Code with exlanataion:

package menu_Exception;

import java.util.*;

public class Main{

public static void main(String []args){
String keepGoing = "y";
Scanner scan = new Scanner(System.in);
while(keepGoing.equals("y") || keepGoing.equals("Y"))
{
System.out.println("1:Add a student");
System.out.println("2:Remove a student");
System.out.println("3:View a student record");
System.out.println("Your choice?(1/2/3) ");
//add try catch to handle exception
try{
   int choice=scan.nextInt();
}
catch (InputMismatchException e)
{
   //print invalid choice and call main() function again
   //to input again
   System.out.print("Invalid choice.\n\n");
   System.out.println("Enter your choice again...");
   main(args);
}
System.out.println("Try again? (y/n) ");
keepGoing = scan.next();
}
System.out.println("Bye");
}
}

-----------------------------------------------------------------------------------------------

Output:

Main.java X 1 package menu_Exception; 2. 3 import java.util.*; e Console x Main (14) [Java Application] C:\Progra 1: Add a st

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