Question

Use the results of Project #2. Recall that you performed a binomial probability experiment 50 times.

In Project #3, you will calculate a 99% Confidence Interval for the true probability of success, a 95% Confidence Interval, and a 90% Confidence Interval.

Which of these intervals contain your original guess? None of them? All of them? Was your original guess accurate or inaccurate? Write a paragraph to explain.

Answer 1

D=50 P read = 30, fail = 20 / Answer Given that Let turnping up head Success Here Sample proportion 30 50 0.6 99%. Confo dance praterval for true pocbability Bate Izel Ê (1-6) for 99% GI Z = 2.58 - 0.6 + 2.58 (0-6)(0-4) 50 = 0.6 + C-1787 = (-42, 0.78) This Confidence interval Contoons origenal guess t.e 0.5 95%. G-I for true probability for 957. G-I Zo=1.96 2-6 1-96 0-680-4 50 - 0.64 0.1358 = (0-46, 0.44) This Confidence internal Contains original guess 90% Confidence interval for true probability 0.6+ 1.65 0.68 0.4 50 for 90% C.I zo = 1.65 0.6 + 0.1143 (0.44, 0.71)

Our OUV This Confidence internal Contouns orginal guess All the intervals Contain original guess so we Can Say that 90%, 95% and 99%. Samples will have our ongenal guess on the Confidence Potervals. so guess as nearly accurate- alote:- It 95 not poseble to find taue paobcbalty of Success, can conclude from the sample proportion whether the interal contar foue probabe poty (interual este martes we