Question

1 10.- 2 7.3.001 For a binomial experiment with successes out of trials, what value do we use as a point estimate for the probability of success pon a single trial? Need Help? Rundt 11.-/1 points understat12 7.3.002 In order to use a normal distribution to compute confidence intervals for p, what conditions on np and ng need to be satisfied? 0 59 5 O np < 5; na s 0 HP > 5, ng > 5 0 0 25, g = 5 Need Help? 12.-/2 points undertat 12 7.3.001 Results of a poll of a random sample of 3003 American adults showed that 20% do not know that caffeine contributes to dehydration The poll was conducted for the Nutrition Information Center and had a margin of error of : 1.4% (a) Does the margin of error take into account any problems with the wording of the survey question, interviewer errors, bias from sequence of questions, and so forth? (b) What does the margin of error reflect? The margin of error reflects the difference between p and . The margin of error reflects the total length of a confidence interval The margin of error reflects the difference between panda The margin of error reflects the difference between pand Need Help? Red

Answer 1

Solution

$\small {\color{Blue} \mathbf{10.}}$

$\small \mathbf{\hat p=}$

$\small {\color{Red} \mathbf{r}}$

$\small {\color{Red} \mathbf{n}}$

Sample proportion (P) = Success number of trail

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$\small {\color{Blue} \mathbf{11.}}$

In order to use a normal distribution to compute confidence intervals for p, the np and nq must be greater than 5.

np > 5: nq > 5

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$\small {\color{Blue} \mathbf{12.}}$

_{(a) No}
, The margin of error deals with sample size, sample proportion and confidence level.

(b) The margin of error reflects the difference between p and p