Question

You are given the following integral: St 2. - 4 ·da 22 +1 On a piece of paper evaluate this integral. Use your working to cho
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Answer #1

\\ I = \int \frac{2x - 4}{x^2 + 1}dx \\ \\ I = \int [\frac{2x}{x^2 + 1} - \frac{4}{x^2 + 1}]dx \\ \\ I = \int \frac{2x}{x^2 + 1} dx - 4 \int \frac{1}{x^2 + 1}]dx \\ \\ I_1 = \int \frac{2x}{x^2+ 1}dx \\ \\ Substitute: \ \ u = x^2 + 1 \\ \\ du = (2x + 0)*dx \\ \\ du = 2x*dx \\ \\ I_1 = \int \frac{1}{u}du = ln (u) + C \\ \\ I_1 = ln (x^2 + 1) + C \\ \\ I_2 = \int \frac{1}{x^2 + 1}*dx = arctan (x) + C \\ \\ So, \\ \\ I = I_1 - 4*I_2 \\ \\ I = ln (x^2 + 1) - 4*arctan (x) + c \\

So steps used are D and I

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