Question

A diatomic gas is at a pressure of 100 kPa, 500 cm3 and 20 ° C (point A), it is carried through the following processes. • Compresses adiabatically with a compression ratio equal to 6 (ie VA / VB = 6). • Then it is heated at constant volume until reaching 1000 K. • Then it expands adiabatically until it reaches the original volume. • Finally it is cooled in a constant volume until reaching the original state. Calculate cycle efficiency Select one: to. a 83.3% yes. b 40.8% C. 61.2% re. 49.2% me. None of the options determined F. 55.1% gram. 23.8% h. 37.6% me. 51.16% j. 14.28%       fast please, it's urgent :(

Answer 1

Let's olaraw the Pov diagra diagram ab of the given process, C Cioab) adiabaſic expansion net work clone figurk/drewn after heating cooling 8.3.33cm 3 jookpa A (293kor 2000) adiabatic compression 500 cm3 the diatomic gas, heat capacity ratio is given as City The effeciency of the cycle can be defined as n = net work done Wext Wco heat added Whet aelded at constant volume, so head is klow the be found as, Rh can Qha ncrOT (1) before finding this we should find the number of moles of working fluid, taking condition A. prms om (200x103) (500 x 10-6) m3 8.314 x 293 .)m PV RT 0.020s moles ein capacity constant volume heat For diatomic gas SR so from (1) 0.0205** (5ķ) (TerTB)

we we Here know the value of Tea 1000 k But need to find the value of To using the adiabatis compression for adiabatic process, IT is related to u as, ratio given a Be TTC WB vo &f Te TA UA JB :) Тв (6)?m=1 (293) & TB & book calculate has so now we 120.137 J She ouaos (SR) (200-600). in adiabatic compression is given ac, done How the work 0.0205 ( SR) (600-293) : 130.81 kJ We now (TB-FA) : 2 can be foundas, done in adiabatt expansion llow the work Wex anave (Tort) Simillanily, as above for adiabatic process, Ve Te orn (+) woo TDi 488.36 k. Wex 30 - 2185 0.02055*(SR) (488.3b- 100o) :

Now i the effeciency is calculated as, 7- 2184 130.81 0.5116 190.437 51.1894 to effeciency of the eyce is