Question

would love help with these! and with checking the answer i have already

Please read the following prompt carefully: "About 48% of all births result in a girl. Suppose a couple is planning to have three children." Determine the following values by rounding to the nearest indicated decimal place. Please type your solution in the text entry boxes provided.

Answer 1

(m) Probability of having atleast two boys

= P(two boys) + P(three boys)

= $\binom{3}{2}*0.52^{2}*0.48+0.52^{3}$ = 0.53

(n) Probability of having atleast two girls

= $\binom{3}{2}*0.48^{2}*0.52+0.48^{3}$ = 0.47

(o) Probability of having atmost one boy

= Probability of having atleast 2 girls

= 0.47

(p) Probability of having atmost one girl

= Probability of having atleast two boys

= 0.53

(q) Probability of having atmost two boys

= 1 - Probability of having all three boys

= 0.8594

(r) Probability of having atmost two girls

= $1-0.48^{3}$ = 0.8894