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question 14 please!

14) (20) Does the presence of others affect peoples willingness to assume responsibility for the welfare of others? For exam
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Answer #1

Objective: To test whether presence of others affect people's willingness to assume responsibility for the welfare of others. From this statement,

a. The independent variable would be - No. of Confederates which is considered to be the treatment with three categories - 0, 2 and 4 confederates

b. The dependent variable would be - The time taken by subjects to ask for help.

c.

Source SS df MS F
Between SSB k-1 MSB=SSB / (k-1) MSB / MSE
Within SSW N-k MSE=SSE / (N-k)
Total 294 N-1

where,

Within Sum of Squares = SS1 + SS2 + SS3

= 14 + 14 + 8

SSW = 36

Between Sum of Squares

=\sum_{i=1}^{k}\frac{T_{i}^{2}}{n_{i}}-\frac{G^{2}}{N}

where, G = 15 + 39 + 54 = 108, N = 3 + 3 + 3 = 9

=\frac{15^{2}+39^{2}+54^{2}}{3}-\frac{108^{2}}{9}

= 1554 - 1296

= 258

We may verify the result obtained be determining whether the sum of the explained (SSB) and unexplained variation (SSW) equals total variation (SST).

Here SSB + SSW = 258 + 36 = 294 which is equal to the Total Sum of Squares.

Next,

No. of treatments compared = k = 3

No. of observations = N = 9

Completing the ANOVA table,

Source SS df MS F
Between 258 3-1=2 MSB=258/2=129 129/6=21.5
Within 36 9-3=6 MSE=36/6=6
Total 294 9-1=8

The test statistic F ~ F(2,6), with critical / rejection region given by, F > Fcritical.

d. The critical value of F can be obtained from F tables by looking for the intersection of row and column corresponding to 2 and 6 df respectively at 5% level of significance.

TABLE E F critical values Degrees of freedom in the numerator р 2 3 4 5 6 7 8 9 .100 .050 .025 .010 .001 39.86 161.45 647.79

Fcritical = 5.14

e. Since, the test statistic F = 21.5 > 5.14 lies in the rejection region of the test, we may reject H0 at 5% level. We may conclude that the data does provides sufficent evidence to support the claim that presence of others affect people's willingness to assume responsibility for the welfare of others.

f. Tukey's HSD is a post hoc test conducted on obtaining a signifcant difference in the means, to determine which pair differs significantly. It is computed using the formula:

HSD = \frac{M_{i}-M_{j}}{\sqrt{\frac{MSW}{n}}}

And the value thus obtained is compared with the critical value of HSD for (k,N-k) df and conclude the difference to be significant if HSD > Critical value. Obtaiing the critical value for (3,16) df from critical value table for Tukey's HSD:

df.k 2 3 4 5 6 7 8 9 10 5 3.64 4.60 5.22 5.67 6.03 6.33 6.58 6.80 6.99 6 3.46 4.34 4.90 5.30 5.63 5.90 6.12. 6.32 6.49 7 3.34

Since Tukey's HSD = 6.14 > 3.65, we may conclude that the means compared were significantly different.

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