Question

13 points) The horsepower (Y, in bhp) of a motor car engine was measured at a chosen set of values of running speed (X. In rp

Part a)

Compute the regression line for these data, and provide your estimates of the slope and intercept parameters. Please round intermediate results to 6 decimal places.

Slope:

Intercept:

Note: For sub-parts below, use the slope and intercept values in Part a, corrected to 3 decimal places to calculate answers by hand using a scientific calculator.

Part b)

Based on the regression model, what level of horsepower would you expect the engine to produce if running at 24002400 rpm?

Answer:

Part c)

Assuming the model you have fitted, if increase the running speed by 100100 rpm, what would you expect the change in horsepower to be?

Answer:

Part d)

The standard error of the estimate of the slope coefficient was found to be 0.0013570.001357. Provide a 95% confidence interval for the true underlying slope.

Confidence interval: (  ,  )

Part e)

Without extending beyond the existing range of speed values or changing the number of observations, we would expect that increasing the variance of the rpm speeds at which the horsepower levels were found would make the confidence interval in (d)

A. either wider or narrower depending on the values chosen.
B. narrower.
C. unchanged.
D. wider.


Part f)

If testing the null hypothesis that horsepower does not depend linearly on rpm, what would be your test statistic? (For this part, you are to calculate the test statistic by hand using appropriate values from the answers you provided in part (a) accurate to 3 decimal places, and values given to you in part (d).)

Answer:

Part g)

Assuming the test is at the 1% significance level, what would you conclude from the above hypothesis test?

A. Since the observed test statistic falls in either the upper or lower 1/2 percentiles of the t distribution with 99 degrees of freedom, we can reject the null hypothesis that the horsepower does not depend linearly on rpm.
B. Since the observed test statistic does not fall in either the upper or lower 1/2 percentiles of the t distribution with 99 degrees of freedom, we cannot reject the null hypothesis that the horsepower does not depend linearly on rpm.
C. Since the observed test statistic does not fall in either the upper or lower 1 percentiles of the t distribution with 99 degrees of freedom, we cannot reject the null hypothesis that the horsepower does not depend linearly on rpm.
D. Since the observed test statistic does not fall in either the upper or lower 1/2 percentiles of the t distribution with 99 degrees of freedom, we can reject the null hypothesis that the horsepower does not depend linearly on rpm.
E. Since the observed test statistic falls in either the upper or lower 1/2 percentiles of the t distribution with 99 degrees of freedom, we cannot reject the null hypothesis that the horsepower does not depend linearly on rpm.

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Answer #1

we have given that 2 de = 36 36 3636 rpm ECHi-æ)2 = 171940000. 0000 rpm 7 = 173. 61ool E Capi-D) (Li-I) = 8299578. 0000 rpm OPart 6) Here we want to find horsepower when rpm = 2400 put x= 2400 to the regression equation we get | 1 (0 0 4 8 2 40o) - -horsepower will be increased by 4.8 bhp part d) know loo(1-2% confidence interval for slope is given as (6. tn 2,42 se (6) 6+

t table as follows:

7:43 62.0 KB/S 774 Edit 26 Х t-distribution Confidence Level 85% 90% 95% 98% 60% 70% 80% 99% 99.8% 99.9% 2 Tailed 1 Tailed 0.

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