Question

You randomly sample a variable from a population. Your sampled values are 1, 3, 4, 4 You compute the sample variance 82. What
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Answer #1

Here, we're given the sample- 1,3,4,4
We're asked to find sample variance and sample s.d.-

To, obtain the sample variance, first we've to obtain the sample mean:
C ΙΣ 2 n 1=1
where,
x_{i}: ith sample value, for all i=1(1)4
n: sample size
\therefore \overline{x}=\frac{1+3+4+4}{4}=\frac{12}{4}=3
Now,
We're to obtain the Sample Variance(s2 )-


Formula for Sample Variance is given by-

s^{2}=\frac{1}{n-1}\sum_{i=1}^{n}(x_{i}-\overline{x})^{2}

  =\frac{1}{4-1}\sum_{i=1}^{4}(x_{i}-3)^{2}
  =\frac{1}{4-1}\left \{ (1-3)^{2}+(3-3)^{2}+(4-3)^{2}+(4-3)^{2} \right \}
=\frac{1}{4-1}\left \{ 6 \right \}
  =\frac{6}{3}
  =2

\therefore Sample Variance is=2

As we know if we take the square root of the Sample variance we'll get the Sample Standard Deviation(s).

Formula for Sample Standard Deviation is given by-

\therefore s=\sqrt{\frac{1}{n-1}\sum_{i=1}^{n}(x_{i}-\overline{x})^{2}}
\Rightarrow s=\sqrt{s^{2}}
\Rightarrow s=\sqrt{2}
\Rightarrow s=1.4

\therefore Sample Standard Deviation=1.4

I hope this clarifies your doubt. If you're satisfied with the solution, hit the Like button. For further clarification, comment below. Thank You. :)



  

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