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Consider the region bounded by y = (1 - 2)2 and y = 4 - r. For each of the following, set up (but do not compute) integrals t

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2 y = (06-2² TE and y = 4-3 For intersection (6-2) ² = 4x x²+4-4x=4-10 x²_3x = 0 X=u, y = 4, y = 1 y=4-X 2 3 y=(x-2) 2 V = volume of solid of rotation of about y-ati 2 For Shell method R(2)=0 H(0) = (4x) - (0-2) osx{3 لما V = San 21 R(x) H(x) d

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