Solution:
We are given the data on difference between the observed fraction and the expected fraction of tail, for 6 trials from a sample of size 10.
Using R, standard deviation is computed as:
> fraction = c(-0.2,-0.2,-0.1,-0.2,0,0.1)
# Computing standard deviation usin function sd() > standrd_deviation = sd(fraction) > standrd_deviation [1] 0.1264911 # Computing standard deviation by variance, > variance = var(fraction) > variance [1] 0.016 > sqrt(variance) [1] 0.1264911
Hence standard deviation of the given data is 0.1265
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